Vietnamese badminton players will be pitted against strong opponents at the Ciputra Hanoi-Vietnam Challenge 2010 at the Trinh Hoai Duc Gymnasium on April 20.

The tournament will draw 260 athletes from 15 teams including Indonesia, China, Japan, Malaysia and Australia, who will be competing in men's and women's singles, doubles and mixed doubles for a total of 15,000 USD in cash prizes.

According to the draw, Vietnamese Van Tuan Kiet will clash with 27th world-ranked Shon Wan-ho from the Republic of Korea Korea in the men's singles opener, while Phung Nguyen Phuong Nhi meets Chen Jiayuan of Singapore in the women's singles.

"The tournament, which will draw 50 of the world's top badminton players, is a chance for youngsters to hone their skills and improve their world rankings," said Vietnam Badminton Federation (VBF)'s general secretary Le Thanh Sang.

Sang also said the top Vietnamese player, Nguyen Tien Minh, who won the men's singles title last year, will not compete in the event as he is now competing on bigger tours.

In the women's doubles, Le Thi My Linh and Pham Thi Trang will test Singaporean Chen Jiayuan and Gu Juan in the first round.

At the tournament, the host will show off a squad of youngsters that have trained since 2006 including Duong Phuong Nam , Bui Bang Duc, Nguyen Ngoc Tung and Dao Manh Thang.

The VBF also said the winner from each event will get 4,000 bonus-points from the World Badminton Federation and 1,250 USD in cash prize./.